Get Answers to all your Questions

header-bg qa

Identify the correct 3-D figure from amongst the answer figures, which has the same elevation, as given in the problem figure on the left

Option: 1


Option: 2


Option: 3


Option: 4


Answers (1)

best_answer

g(x)\begin{Bmatrix} \sqrt[k]{x+1}& 0\leqslant x\leqslant 3\\ mx+2 & 3\leqslant x\leqslant 5 \end{Bmatrix}

g{}'(x)\begin{Bmatrix}\frac{k}{\sqrt[2]{x+1}} & 0\leqslant x\leqslant 3\\ m & 3< x\leqslant 5 \end{Bmatrix}

\because \frac{K}{\sqrt[2]{3+1}}=m

\therefore K=4m------------(i)

Now g(n) is continuous at x=3

\therefore \sqrt[K]{3+1}=3m+2

2K=3m+2

2X4m=3m+2

8m=3m+2

5m=2

m=\frac{2}{5}

=>K=\frac{8}{5}

\therefore m+K=\frac{2+8}{5}=\frac{1D}{S}=2

Posted by

Nehul

View full answer