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  • If 15 AMs are inserted between 1 and 31,then the common difference between them isOption: 1 2Option: 2<

If 15 AMs are inserted between 1 and 31,then the common difference between them is

Option: 1

2


Option: 2

1


Option: 3

3


Option: 4

none of these


Answers (1)

best_answer

As we learnt

Common difference between the AMs (d) -

d=\frac{b-a}{n+1}

where a is the first term, b is the last term, n is number of mean inserted .

In this question,

 d=\frac{31-1}{15+1}= \frac{30}{16}

 

Posted by

Ajit Kumar Dubey

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