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  • If 3 consecutive terms of a GP are selected such that their product is 64 and sum of squares is 84. Find the terms.Option: 1 2,4,8<div

If 3 consecutive terms of a GP are selected such that their product is 64 and sum of squares is 84. Find the terms.

Option: 1

2,4,8


Option: 2

-2,4,-8


Option: 3

1,2,4


Option: 4

Both (a) and (b)


Answers (1)

best_answer

As we learnt

Selection of terms in G.P.

If we have to take three terms in GP, we take them as \frac{a}{r},a,ar

 

Now,

Let terms are  \frac{a}{r},a,ar 

So,  \frac{a}{r}.a.ar=64

hence, a3 = 64 and a = 4

\left (\frac{4}{r} \right )^{2}+4^{2}+\left (4r \right )^{2}=84\: \:

Thus, r=\pm 2

Terms are 2,4,8 or -2,4,-8

Posted by

Ritika Harsh

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