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  • If -3 lies between the roots of the equation  then p lies in<di

If -3 lies between the roots of the equation x^2+px+6=0 then p lies in

Option: 1

p\in(-\infty, -\sqrt{24})\cup ( \sqrt{24},\infty)


Option: 2

p\in ( \sqrt{24},\infty)


Option: 3

p\in(-\infty, -\sqrt{24})\cup ( 5,\infty)


Option: 4

p\in ( 5,\infty)


Answers (1)

If -3 lies between the roots

\begin{array}{l}{\therefore \quad a f(k)<0} \\ \Rightarrow \quad 1 \cdot f(-3)<0 \\ \Rightarrow \quad 9+ p(-3)+6<0 \quad \\\Rightarrow \quad 15-3p>0 \\ {\Rightarrow \quad p>5}\end{array}

Posted by

Sumit Saini

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