Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If for some c<0, the quadratic equation, <img alt="2 \mathrm{cx}^{2}-2(2 \mathrm{c}-1) \mathrm{x}+3 \mathrm{c}^{2}=0" src="https://entrancecorner.oncodecogs.com/gif.latex?2%20%5Cmathrm%7Bcx%7D%5

If for some c<0, the quadratic equation, 2 \mathrm{cx}^{2}-2(2 \mathrm{c}-1) \mathrm{x}+3 \mathrm{c}^{2}=0 has two distinct real roots, \frac{1}{\mathrm{a}} \text { and } \frac{1}{\mathrm{b}} , then the value of the determinant \left[\begin{array}{ccc}{1+a} & {1} & {1} \\ {1} & {1+b} & {1} \\ {1} & {1} & {1+c}\end{array}\right] is

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

For two distinct real roots 

 As Sum of the roots = - \frac{B}{A} 

So \frac{1}{a}+\frac{1}{b}=2-\frac{1}{c}

And the product of the roots = \frac{C}{A}?

 So \frac{1}{a}*\frac{1}{c}=\frac{3}{2}c\Rightarrow \frac{2}{3}=abc?

And

  ?=abc[1+\frac{1}{a}+\frac{1}{b}+\frac{1}{c}] ?=abc[1+2-\frac{1}{c} +\frac{1}{c}] ?= 3abc= 3*\frac{2}{3}=2?

Posted by

himanshu.meshram

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Calculate JEE Main 2025 rank using predictor tool for admission to top IITs, NITs, IIITs
anam-khan

NTA drops 1 out of 9 flagged errors from JEE Mains final answer key 2025
anam-khan

Consumer protection watchdog warns coaching centres against misleading ads ahead of IIT-JEE Main results

Latest Question