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If the angle between the normal to the parbola \mathrm{ x^2=4 ay} at poirt \mathrm{ P} and the focal chord passing through \mathrm{ P} is \mathrm{ \frac{\pi}{3},} then square of the sope af the tangent at point\mathrm{ P} is \mathrm{ \frac{1}{n}}. The value of \mathrm{ A}  is

Option: 1

3


Option: 2

1


Option: 3

4


Option: 4

0


Answers (1)

best_answer

By property, \mathrm{\angle M^{\prime} P T=\angle S P T=30^{\circ}}


Now, slope of tangent \mathrm{=m=\tan \angle M^{\prime} T P=\tan 30^{\circ}=\frac{1}{\sqrt{3}}}

Therefore,\mathrm{ m^2=\frac{1}{3}.}

Posted by

Gaurav

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