Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If the distance between the foci of an ellipse is 5 and the distance between its directrices is 12, then the length of its latus rectum is:Option: 1</s

If the distance between the foci of an ellipse is 5 and the distance between its directrices is 12, then the length of its latus rectum is:

Option: 1

\begin{aligned} & \frac{119}{25} \\ \end{aligned}


Option: 2

\frac{109}{25} \\


Option: 3

\frac{109}{20} \\


Option: 4

\frac{109}{15}


Answers (1)

best_answer

\begin{aligned} =e^2=1-\frac{b^2}{a^2} \\ \Rightarrow \frac{1}{2}=1-\frac{b^2}{18} \\ \Rightarrow \frac{1}{2}=\frac{b^2}{18} \end{aligned}

\Rightarrow b^2=9

Length of latus rectum  =\frac{2 b^2}{a}

                                        =\frac{119}{25}

Posted by

Divya Prakash Singh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: BTech civil engineering cut-offs at NITs show steady demand after years of decline
anam-khan

JEE Main 2026 Registration LIVE: NTA session 1 application link active at jeemain.nta.nic.in; apply by Nov 27
anam-khan

JEE Main 2026: IIT Delhi closing ranks for top BTech courses under open category

Latest Question