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  • If the molecule of HCl were totally polar, the expected value of dipole moment is D(debye) but the experimental value of

If the molecule of HCl were totally polar, the expected value of dipole moment is 6.12 D(debye) but the experimental value of dipole moment was 1.03D. The percentage ionic character is:

Option: 1

17


Option: 2

83


Option: 3

50


Option: 4

Zero


Answers (1)

best_answer

As we have learnt,

Percentage ionic character is given by the following formula

\mathrm{\%\ Ionic \ Character=\frac{experimental\, value\, of\, dipole\, moment}{theoretical\,value\, of\, dipole\, moment }\times 100=\frac{1.03D}{6.12D}\times 100=16.83 \% = 17\%}

Hence, option number (1) is correct

Posted by

Riya

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