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If  x+iy= \frac{3+4i}{3-4i}  then x^{2}+y^{2} equals 

Option: 1

1


Option: 2

2


Option: 3

3


Option: 4

4


Answers (1)

Given,\,\, x+iy= \frac{3+4i}{3-4i}

Since these 2 complex numbers are equal, so their mod will also be equal

|x + iy| = |\frac{3+4i}{3-4i}| = \frac{|3+4i|}{|3-4i|}= \frac{5}{5} = 1

 

\sqrt{x^{2}+y^{2}}= 1

x^{2}+y^{2}= 1

 

Posted by

Kshitij

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