Comparing both sides
...........(1)
.............(2)
...........(3)
The correct option is (2)
Study 40% syllabus and score up to 100% marks in JEE
50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pKb of ammonia solution is 4.75, the pH of the mixture will be : Option: 1 3.75 Option: 2 4.75
JEE Main Session 2 Result 2026 tomorrow; steps to download, how to calculate marks
JEE Main 2026 Result LIVE: Session 2 scores tomorrow at jeemain.nta.nic.in; cutoff marks, toppers list
JEE Main Marks vs Rank 2026: Category-wise qualifying cut-offs show rise over years
Create Your Account
To keep connected with us please login with your personal information by phone
Dont't have an account? Register Now