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If (a+ib)^5 = p+iq , where i=\sqrt{-1}  then, (b+ia)^5 = ?  

Option: 1

q+ip


Option: 2

p+iq


Option: 3

p-iq


Option: 4

q-ip


Answers (1)

best_answer

(a+ib)^5 = p+iq

Taking conjugate of both sides, we get

(a-ib)^5 = p-iq

This can be written as

(-i^2 a-ib)^5 = -i^2p-iq

Taking -i common on both sides

(-i)^5(ia+b)^5=(-i)(ip+q)

(-i)(ia+b)^5=(-i)(ip+q)

Now (-i) get canceled out from both sides and we are left with 

(b+ia)^5=q+ip

So, correct option is (a)

Posted by

shivangi.shekhar

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