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Imagine an atom made up of proton and a hypotherical particle of double the mass of the electron but having the same charge as the electron. Apply bohr atom model and consider all possible transitions of this hypothetical particle to the first excited level. The longest wave length pohlow that will be emitted has wave length \lambda. equal ts

 

Option: 1

\frac{9}{5}\mathrm{~R}


Option: 2

\frac{36}{5\mathrm{~R}}


Option: 3

\frac{18}{5\mathrm{~R}}


Option: 4

\frac{4}{\mathrm{~R}}


Answers (1)

best_answer

\mathrm{E_n=-\frac{R h c}{n^2} }
Also, \mathrm{ E_n \propto m}

for this hypothetical atom energy in \mathrm{ n^{\text {th }}} orbit will be given by -

\mathrm{E_n=-\frac{2 R h c}{n^2}}

The longest wave length \mathrm{\lambda_{\max }} (or minimum energy) photom will correspond to the transition of particle from n=3 to n=2

\begin{gathered} \mathrm{\therefore \quad \frac{h c}{\lambda_{\text {max }}}=E_3-E_2=2 h c\left(\frac{1}{2^2}-\frac{1}{3^2}\right)} \\ \mathrm{\lambda_{\text {max }}=18 / 5 \mathrm{R} \text { Ans }} \end{gathered}
 

Posted by

Ritika Jonwal

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