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When connected to position 1, balancing point of potentiometer wire is obtained at 80cm from A, and when connected to position 2, balancing point is obtained at 120 cm. Then which of the following is true
Option: 1
$3E_{1}=2E_{2}$

Option: 2
$E_{2}=E_{1}$

Option: 3
$3E_{2}=2E_{1}$

Option: 4
$E_{2}=3E_{1}$

Answers (1)

best_answer

$\frac{E_{2}}{E_{1}}=\frac{80}{120}=\frac{2}{3}$

$3E_{2}=2E_{1}$

Posted by

Devendra Khairwa

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