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In a 20 m deep lake, the bottom is at 4°C. The air temperature is constant –10°C. The thermal conductivity of ice is 4 times that of
water. Neglecting expansion of water at freezing. The maximum thickness of ice will be

Option: 1

\frac{20}{11}m


Option: 2

\frac{200}{11}m
 


Option: 3

15 m

 


Option: 4

5 m


Answers (1)

best_answer

At maximum thickness rate of flow of heat will be same

\frac{KA\: (4-0)}{20-x}=\frac{4KA\: \left [ 0-\left ( -10 \right ) \right ]}{x}\\x=\frac{200}{11}m

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