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In a common-base mode of a transistor, the collector current is 5.488 \mathrm{~mA} for an emitter current of 5.60 \mathrm{~mA}. The value of the base current amplification factor (\beta) will be

Option: 1

49


Option: 2

50


Option: 3

51


Option: 4

48


Answers (1)

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\mathrm{\begin{aligned} & \beta=\frac{I_C}{I_B} \text { and } I_E=I_C+I_B \\ & \therefore=\frac{I_C}{I_E-I_C}=\frac{5.488}{5.60-5.488}=49 \end{aligned} }

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