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  • In a cuboid of dimension 2L × 2L × L, a charge q is placed at the center of the surface ' S ' having area of 4L2 .The flux through the opposite surface to '

In a cuboid of dimension 2L × 2L × L, a charge q is placed at the center of the surface ' S ' having area of 4L2 .The flux through the opposite surface to ' S ' is given by

 

Option: 1

\frac{q}{12\varepsilon _o}


Option: 2

\frac{q}{6\varepsilon _o}


Option: 3

\frac{q}{3\varepsilon _o}


Option: 4

\frac{q}{2\varepsilon _o}


Answers (1)

best_answer

box is considered on the given box then charge ‘q’ will be at center.
So flux from surface S^{\prime}=\left(\frac{q}{\varepsilon_0}\right) \cdot \frac{1}{6}=\frac{q}{6 \varepsilon_0}

Posted by

Gaurav

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