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In a face centred cubic lattice, atom occupies the corner positions and atom occupies the face centre positions. If one atom of is missing from one of the face centred points, the formula of the compound is

Option 1)  A_{2}B\;

Option 2)  \; AB_{2}\;

Option 3)  \; A_{2}B_{3}\;

Option 4)  \; A_{2}B_{5}

Answers (1)

best_answer

As we learnt in

No. of atoms(z) for face centered unit cell -

Lattice points: at corners and face centers of unit cell.

For face centered cubic (FCC), z=4.

- wherein

 

 

No. of atoms(z) for simple cubic unit cell -

Lattice points: at corners

For simple cubic (SC), z=1

- wherein

 

Number of atom A per unit cell =8\times \frac{1}{8}=1

Number of atom B per unit cell =5\times \frac{1}{2}=\frac{5}{2}

AB5/2 i.e. A2B5

Correct option is 4.

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avinash.dongre

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