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In a hollow symmetrical cone which have symmetry about the x-axis and the vertex of the cone is at \left ( 2,0,0 \right ), then the
coordinate of the center of mass of the mentioned hollow cone is (Height of the cone is 30\; cm) -

 

 

Option: 1

\left ( 2,22,0 \right )


Option: 2

\left ( 20,0,0 \right )


Option: 3

\left ( 0,20,0 \right )


Option: 4

\left ( 22,0,0 \right )


Answers (1)

best_answer

 

 

 

Since the vertex of the cone is at (2,0,0), so the distance of the center of mass of hollow cone is at a distance of y_{cm}=\frac{2H}{3} from the vertex. So, the y_{cm} from the vertex is \frac{2H}{3}=\frac{2\times 30}{3}=20 \: cm  From the vertex

Now, the x coordinate is- 20+2=22\; cm

And the y and z coordinates will not change because it is symmetrical in shape.
Option - (d) is correct

Posted by

jitender.kumar

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