Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • In a hydrogen atom, if energy of an electron in ground state is then that in the 2nd excited state is:<div class='q

In a hydrogen atom, if energy of an electron in ground state is -13.6eV then that in the 2nd excited state is:

Option: 1

1.51eV


Option: 2

3.4eV


Option: 3

6.04eV


Option: 4

13.6eV


Answers (1)

best_answer

 

radius, velocity and the energy of the nth orbital -

Bohr radius of nth orbit :

r_{n}= 0.529 \frac{n^{2}}{z}A^{0}

where Z is atomic number

velocity of electron in nth orbit :

v_{n}= (2.165\times 10^{6})\frac{z}{n}\: m/s

where z is atomic number

Total energy of elctron in nth orbit :

E_{n}= -13.6\: \frac{z^{2}}{n^{2}}eV

Where z is atomic number

-

 

 As we have learnt,

The second excited state is actually the 3 orbital.
Therefore, we have:

\begin{array}{l}{E_{n}=\frac{-13.6}{n^{2}} e V} \\ {\text { or }}\\ {\text E=\frac{-13.6}{9} e V=-1.5 e V}\end{array}

Therefore, Option(1) is correct

Posted by

Pankaj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 chemistry needs conceptual understanding; 5 tips to score high
anam-khan

JEE Main 2025 exam city intimation slip for session 1 soon; paper pattern, exams from January 22
anam-khan

JEE Main Maths 2025: Five tips to score high marks in ‘toughest’ subject; most important chapters

Latest Question