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  • In a medium the speed of light wave decreases to times to its speed in free space The ratio of relative permittivity to t

In a medium the speed of light wave decreases to 0.2 times to its speed in free space The ratio of relative permittivity to the refractive index of the medium is \mathrm{ x: 1}. The value of \mathrm{ x} is (Given speed of light in free space \mathrm{= 3 \times 10^{8} m s^{-1}} and for the given medium \mathrm{\mu _{r}=1})

Option: 1

5


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{V=\frac{c}{n}}

\mathrm{n\rightarrow refractive \: index}

\mathrm{n=\frac{c}{0.2c}=5}

\mathrm{n=\sqrt{\mu_{r}\varepsilon _{r}}}

\mathrm{ \varepsilon_r=n^2=25 }

\mathrm{\frac{\varepsilon_r}{n}=\frac{25}{5}=\frac{5}{1}}
 

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Riya

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