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In a population of N families, 50 % of the families have three children, 30% of the families have two children and the remaining families have one child. What is the probability that a randomly picked child belongs to a family with two children?

Option: 1

\frac{3}{23}


Option: 2

\frac{6}{23}


Option: 3

\frac{3}{10}


Option: 4

\frac{3}{5}


Answers (1)

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Number of children belonging to families with 3 children

                    =(50 \% \text { of } \mathrm{N}) \times 3=\frac{3 \mathrm{~N}}{2}

Number of children belonging to families with 2 children

                     \mathrm{=(30 \% \text { of } N) \times 2=\frac{3 N}{5}}

Number of children belonging to families with 1 child

                      \mathrm{=(20 \% \text { of } N) \times 1=\frac{N}{5}}

Required probability \mathrm{=\frac{\frac{3 N}{5}}{\frac{3 N}{2}+\frac{3 N}{5}+\frac{N}{5}}=\frac{6}{23}}

          

Posted by

Pankaj Sanodiya

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