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In a simple hydraullic press, cross-sectional area of the two cylinders is $5\times 10^{-4} m^2$ and $10^{-2} m^2$ , respectively. A force of 20 N is applied at the small plunger, then what is the thrust (In N) exerted on the large plunger?
Option: 1 100

Option: 2 200

Option: 3 400

Option: 4 300

Answers (1)

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$F_{2}=F_{1} \times\left(\frac{A_{2}}{A_{1}}\right)=20 \times \frac{10^{-2}}{5 \times 10^{-4}}=400 \mathrm{N}$

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shivangi.shekhar

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