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  • In a Young's double slit experiment, the intensities at two points, for the path differences <img alt="\frac{\lambda}{4}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cfrac%7B%5Clambd

In a Young's double slit experiment, the intensities at two points, for the path differences \frac{\lambda}{4} and \frac{\lambda}{3} (\lambda  being the wavelength of light used) are I_{1} and I_{2} respectively. If I_{0} denotes the intensity produced by each one of the individual slits, then \frac{I_{1}+I_{2}}{I_{0}}=___________.

Option: 1

3


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{I}=4 \mathrm{I}_{0} \cos ^{2} \frac{\phi}{2}
\Delta \phi=\frac{2 \pi}{\lambda} \times \Delta \mathrm{x}
\mathrm{I}_{1}=4 \mathrm{I}_{0} \cos ^{2} \frac{\pi}{4}=2 \mathrm{I}_{0}
\mathrm{I}_{2}=4 \mathrm{I}_{0} \cos ^{2} \frac{2 \pi}{3}=\mathrm{I}_{0}
\Rightarrow \frac{\mathrm{I}_{1}+\mathrm{I}_{2}}{\mathrm{I}_{0}}=3

Ans: (3)

Posted by

shivangi.bhatnagar

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