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In an experiment on photoelectric effect the frequency \mathrm{v} of the incident light is plotted against the stopping potential \mathrm{V_0} . The work function of the photoelectric surface is given by (\mathrm{e} is electronic charge):

Option: 1

\mathrm{OB} \times \mathrm{e} \text{ in } \mathrm{eV}


Option: 2

\mathrm{OB}\text{ in volt}


Option: 3

\mathrm{OA} \text{ in } \mathrm{eV}


Option: 4

 The slope of the line \mathrm{AB}


Answers (1)

best_answer

According to Einstein's equation, \mathrm{hv}=\phi_0+\mathrm{K}_{\max }

Where, \phi_0 is the work function.

\begin{aligned} & \Rightarrow \mathrm{hv}=\phi_0+\mathrm{eV} \\ & \Rightarrow \mathrm{V}_0=\frac{\mathrm{hv}}{\mathrm{e}}-\frac{\phi_0}{\mathrm{e}} \end{aligned}
Comparing with equation, \mathrm{y=m x+c}

\phi_0=-(\text { intercept) } \times \mathrm{e}=\mathrm{OB} \times \mathrm{e} \text { in } \mathrm{eV}

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vinayak

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