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  • In an isochoric process if    <img alt="T_1 = 27 ^{\circ}C\: \: and \: \: T_2 = 127 ^{\circ}C" src="/latex-image/?T_1%20%3D%2027%20%5E%7B%5Ccirc%7DC%5C%3A%20%5C%3A%20and%20%5C%3A%20%

In an isochoric process if    T_1 = 27 ^{\circ}C\: \: and \: \: T_2 = 127 ^{\circ}C Then P_1 / P_2  will be equal to 

Option: 1

9/59


Option: 2

2/3 


Option: 3

3/4 


Option: 4

None of these 


Answers (1)

best_answer

As we have learned

Isochoric Process -

When a Thermodynamic Process undergoes a physical change in such a way that its volume remain constant.
 

- wherein

V= constant

\therefore \frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}

 

 In isochoric process volume remain constant 

At constant volume

 P \propto T \\\\ \Rightarrow \frac{P_1 }{P_2} = \frac{T_1}{T_2} = \frac{273+27}{273+127} = \frac{300}{400 } = \frac{3}{4}

 

Posted by

Ritika Harsh

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