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  • In Freundlich adsorption isotherm, the value of (1/n) is Option: 1 1 in case of physical adsorption<div class='qna-optio

In Freundlich adsorption isotherm, the value of (1/n) is 

Option: 1

1 in case of physical adsorption


Option: 2

1 in case of chemisorption


Option: 3

Between 0 and 1 all cases


Option: 4

Between 2 and 4 in all cases


Answers (1)

best_answer

Freundlich isotherm explains the behaviour of adsorption in an approximate manner. The factor (1/n) can have values between 0 and 1 (probable range 0.1 to 0.5).

Equation:

\log \frac{x}{m}=\log k+\frac{1}{n} \log p

When 1/ n = 0, x m = constant, the adsorption is independent of pressure.

When 1/n = 1, x m = k p, i.e. x m ∝ p, the adsorption varies directly with pressure.

So, option 3 is correct.

Posted by

himanshu.meshram

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