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In how many distinct ways can 21 students be arranged around a circular table, if 12 students are absent on that day?

 

Option: 1

66,022


Option: 2

40,320


Option: 3

65,789


Option: 4

82,450


Answers (1)

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The number of distinct ways to arrange the 9 present students around a circular table is \mathrm{\left ( n-1 \right )!}.
In this case, n = 9, so the number of distinct ways to arrange the 9 present students around a circular table is \mathrm{\left ( 9-1 \right )!}= 8!.
Calculating  \mathrm{8!}, we get:

\mathrm{8 !=8 \times 7 \times 6 \times \ldots \times 3 \times 2 \times 1=40,320}

Therefore, there are 40,320 distinct ways to arrange the 21 students around a circular table when 12 students are absent.

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shivangi.shekhar

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