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  • In terms of resistance R and time T, the dimensions of ratio mu/epsilon of the permiability mu and permittivity epsilon is

  1. [RT^-2]
  2. [R^2 T^-1]
  3. [R^2]
  4. [R^2T^2]

Answers (1)

best_answer

DIMENSION OF PERMEABILITY \mu = [MLT^{-2}I^{-2}]

DIMENSION OF PERMITTIVITY \epsilon = [M^{-1}L^{-3}T^{4}I^{2}]

DIMENSION OF  \mu/\epsilon = [M^{2}L^{4}T^{-6}I^{-4}]

DIMENSION OF RESISTANCE = [ML^{2}T^{-3}I^{-2}] = [R]

As we can see

DIMENSION OF \mu/\epsilon in terms of R and T= [R^{2}]

 

Posted by

Vishwash Tetarwal

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