In the following structure, the double bonds are marked as I, II, III and IV Geometrical isomerism is not possible at site (s) :
Option: 1 III
Option: 2 I
Option: 3 I and II
Option: 4 III and IV
Geometrical isomerism is not possible at Site I as two identical methyl groups are attached to the same carbon bearing the double bond.
Hence, the answer is Option (2)
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