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  • In the given circuit, with steady current, the potential drop across the capacitor must be <img alt="" src="https://cdn.entrance360.com/media/uploads/2018/06/26/17241.jpg" style="height:2

In the given circuit, with steady current, the potential drop across the capacitor must be

Option: 1

V


Option: 2

V/2


Option: 3

V/3


Option: 4

2V/3


Answers (1)

best_answer

As we learnt

 

Change in Potential in traversing a capacitor from negative to positive -

 

+ \frac{q}{C}

- wherein

 

 

In the steady state conduction no current will flow through the capacitor C.

I=\frac{2V-V}{2R+R}= \frac{V}{3R}

P.D between A & B is

V_A-V+V+IR=V_B\: \: or\: \: V_B-V_A= IR= \frac{V}{3}

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