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In the given figure, the face \mathrm{ A C} of the equilateral prism is immersed in a liquid of refractive index \mathrm{ ' n '.} For incident angle \mathrm{ 60^{\circ}} at the side \mathrm{ A C,} the refracteel light beam just grazes along face \mathrm{ A C. }The refractive index of the liquid \mathrm{ n=\frac{\sqrt{x}}{4}.}
The value of \mathrm{ x} is _________________. \mathrm{\text { (Given refractive index of glass }=1.5 \text { ) }}

Option: 1

27


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

For refraction on surface AC,

\mathrm{ i=60^{\circ}, r=90^{\circ} }

By Snell's Law,

\mathrm{(105) \sin 60^{\circ}=n \sin 90^{\circ}}

\mathrm{n=\frac{3}{2} \times \frac{\sqrt{3}}{2}=\frac{3 \sqrt{3}}{4} }

\mathrm{n=\frac{\sqrt{27}}{4} }

\mathrm{x=27 }

Posted by

Sumit Saini

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