Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • In the reaction <img alt="\mathrm{{ }_1^2 \mathrm{H}+{ }_1^3 \mathrm{H} \rightarrow{ }_2^4 \mathrm{He}+{ }_0^1 n}" src="/latex-image/?%5Cmathrm%7B%7B%20%7D_1%5E2%20%5Cmathrm%7BH%7D&plus;%7B%20%

In the reaction \mathrm{{ }_1^2 \mathrm{H}+{ }_1^3 \mathrm{H} \rightarrow{ }_2^4 \mathrm{He}+{ }_0^1 n}. If the tending energies of \mathrm{{ }_1^2 \mathrm{H},{ }_1^3 \mathrm{H}} and \mathrm{{ }_2^4 \mathrm{He}} are respectively \mathrm{\mathrm{a}, \mathrm{b}} and \mathrm{c} (in \mathrm{\mathrm{MeV}}), then the energy (in \mathrm{\mathrm{MeV}}) released in this reaction is

Option: 1

\mathrm{c+a-b}


Option: 2

\mathrm{c-a-b}


Option: 3

\mathrm{a+b+c}


Option: 4

\mathrm{a+b-c}


Answers (1)

best_answer

During fusion binding energy of daughter nucleus is always greater than the total energy of the parent nuclei so energy released = \mathrm{c-\left ( a+b \right )= c-a-b}

Posted by

qnaprep

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: IIT Delhi’s CSE, EE most opted; last 2 year’s closing ranks for all categories
anam-khan

Must provide CBSE 11th registration numbers to JEE Mains aspirants, board tells schools
anam-khan

JEE Main 2026: Engineering at NIT Surathkal tougher for insiders, show BTech cut-offs

Latest Question