Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • In the series reaction given below: <img alt="P \stackrel{k_1}{\longrightarrow} Q \stackrel{k_2}{\longrightarrow} R \stackrel{k_3}{\longrightarrow}\mathrm{ S \text { if }~ k_1>k_3, k_2&lt

In the series reaction given below:
P \stackrel{k_1}{\longrightarrow} Q \stackrel{k_2}{\longrightarrow} R \stackrel{k_3}{\longrightarrow}\mathrm{ S \text { if }~ k_1>k_3, k_2<k_3 }
and \mathrm{ k_1>k_2} then the RDS step of the reaction is
 

Option: 1

\mathrm{ P \rightarrow Q}


Option: 2

\mathrm{ R \rightarrow S}


Option: 3

\mathrm{Q \rightarrow R}


Option: 4

any step
 


Answers (1)

best_answer

 By Given information:
\mathrm{k_1>k_3>k_2} smallest
Means \mathrm{Q \rightarrow R} is the slowest
Step (RDS)

Posted by

Pankaj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Marks vs Percentile 2025: How many marks do you need to score 95+ percentile?
anam-khan

JEE Main 2025 session 1 official answer key out; challenge by February 6; how to calculate NTA score?
anam-khan

JEE Main 2025: NIT Raipur's CSE cut-offs drop; closing ranks in popular branches

Latest Question