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N\! H_{3} is stronger lewis base in comparison to P\! H_{3}  because:

Option: 1

In N\! H_{3} lone pair is present in one of the sp^{3} hybridised orbital while in P\! H_{3}  lone pair is present in pure s-orbital.


Option: 2

In N\! H_{3} lone pair is present in pure s- orbital while in P\! H_{3} lone pair is present in one of the sp^{3}  hybridised orbital.


Option: 3

In N\! H_{3} lone pair is present in one of the sp^{3} d hybridised orbital while in P\! H_{3} lone pair is present in pure s- orbital


Option: 4

None


Answers (1)

best_answer

In N\! H_{3} lone pair is present in one of the sp^{3} hybridised orbital while in P\! H_{3} lone pair is present in pure s-orbital.

Hence, lone pair donation capacity of N\! H_{3} is stronger than P\! H_{3} .

Therefore, option number(1) is correct.

Posted by

Ritika Jonwal

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