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  • Let A and B be two sets containing four and two elements respectively

Let A and B be two sets containing four and two elements respectively. Then the number of subsets of the set A x B, each

having at least three elements is :

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\\\text{Given, } $n(A)=4, n(B)=2$ \\\\ $\therefore n(A \times B)=8$ \\\\ \text{Thus the number of subsets of A} \times \text{B having at least 3 elements } $$ \\\\ =2^{8}-8 C_{0}-{ }^{8} C_{1}-{ }^{8} C_{2}=256-1-8-28=219 $$

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