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  • Let <img alt="\mathrm{P \equiv(-1,0), Q \equiv(0,0)\: and \: R \equiv(3,3 \sqrt{ } 3)}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BP%20%5Cequiv%28-1%2C0%29%2C%20Q%20%5Cequiv%2

Let \mathrm{P \equiv(-1,0), Q \equiv(0,0)\: and \: R \equiv(3,3 \sqrt{ } 3)} be three points. Then the equation of the bisector of the angle \mathrm{P Q R} is

Option: 1

\mathrm{\frac{\sqrt{3}}{2} \cdot x+y=0}


Option: 2

\mathrm{x+\sqrt{3} \cdot y=0}


Option: 3

\mathrm{\sqrt{ } 3 x+y=0}


Option: 4

\mathrm{x+\frac{\sqrt{3}}{2} y=0}


Answers (1)

best_answer

Inclination as Q R is 60^{\circ}, clearly angle bisector will be inclined at an angle of 120^{\circ} with the x-axis.

Hence (C) is the correct answer.

 

Posted by

Pankaj Sanodiya

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