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Light enters from air into a given medium at an angle of $45^{\circ}$ with interface of the air-medium surface. After refraction, the light ray is deviated through an angle of $15^{\circ}$ from its original direction. The refractive index of the medium is :
Option: 1
$1.732$

Option: 2
$1.333$

Option: 3
$1.414$

Option: 4
$2.732$

Answers (1)

best_answer

$\mathrm{i =45^{\circ} }$

$\mathrm{r =30^{\circ} }$

$\mathrm{\mu_1 \sin i =\mu_2 \sin r }$

$\mathrm{1\left(\sin 45^{\circ}\right) =\mu \times \sin 30^{\circ} }$

$\mathrm{\mu =\sqrt{2}=1.414}$

Hence 3 is correct option

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