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Methylation of \mathrm{10\ g} of Benzene gave \mathrm{9.2\ g} of toluene. Calculate the percentage yield of toluene _______. (Nearest integer)
 

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The reaction is

\text { Moles of Benzene }=\frac{10}{78}

\\\therefore \text{Theoretical moles of Toluene} =\frac{10}{78}\\ \\\text{while, actual moles of Toluene} =\frac{9.2}{92}

                                                                    =0.1

\begin{aligned} \therefore \text { yield } &=\frac{\text { Actual moles }}{\text { Theoretical moles }} \times 100 \\ &=\frac{0.1}{\frac{10}{78}} \times 100 . \\ &=78 \% \end{aligned}

Hence, the answer is (78)

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sudhir.kumar

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