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Molecules of an ideal gas are known to have 3 translatinal D.O.F and two rotational D.O.F. The gas is maintained at temperature T. The total internal energy, U of a mole of this gas and the value of  \gamma \left ( =\frac{cp}{cv} \right ) are given respectively, by:
Option: 1 U=\frac{5}{2}RT and  \gamma =\frac{6}{5}
Option: 2 U= 5 \: RT and  \gamma =\frac{6}{5}
Option: 3 U=\frac{5}{2}RT  and \gamma =\frac{7}{5}
Option: 4 U= 5 \: RT and \gamma =\frac{7}{5}

Answers (1)

best_answer

For 1 mole  U=\frac{fRT}{2}  and  \gamma =\frac{C_p}{C_v}=\frac{f+2}{f}

So if U=5RT then we get f= 10 (which is not possible)

and  U=\frac{5}{2}RT then we get f= 5 and  \gamma =\frac{C_p}{C_v}=\frac{f+2}{f}=\frac{7}{5}

So option C is correct

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Deependra Verma

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