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  • Need clarity, kindly explain! 5.325 g sample of Methyl Benzoate, a compound used in the manufacturing of perfumes, is found to contain 3.758 g of Carbon, 0.316 g of Hydrogen and 1.251 g of Oxygen. What is the empirical formula of the compound?

5.325 g sample of Methyl Benzoate, a compound used in the manufacturing of perfumes, is found to contain 3.758 g of Carbon, 0.316 g of Hydrogen and 1.251 g of Oxygen. What is the empirical formula of the compound?

  • Option 1)

    C4H4O

  • Option 2)

    C2H4O

  • Option 3)

    C2H2O

  • Option 4)

    C4H3O

 

Answers (1)

best_answer

As we have learnt,

 

Empirical formula -

An Empirical formula represents the simplest whole number ratio of various atoms present in a compound.

- wherein

for glucose, empirical formula is CH2O

 

Element % Mole ratio Simpleest mole ratio
C \frac{3.758\times 100}{5.325} = 70.57 \frac{70.57}{12} = 5.88 \frac{5.88}{1.47} = 4
H \frac{0.316\times 100}{5.325} = 5.93 \frac{5.93}{1} = 5.93 \frac{5.93}{1.47} = 4
O \frac{1.251\times 100}{5.325} = 23.50 \frac{23.50}{16} = 1.47 \frac{1.47}{1.47} = 1

So, Emepirical formula is C4H4O


Option 1)

C4H4O

Option 2)

C2H4O

Option 3)

C2H2O

Option 4)

C4H3O

Posted by

Plabita

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