Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Need clarity, kindly explain! - Co-ordination Compounds - JEE Main-4

Considering H_2O as a weak field ligand, the number of unpaired electrons in [Mn(H_2O)_6]^{2+} will be (At. No. of Mn = 25)

  • Option 1)

    Two

  • Option 2)

    Four

  • Option 3)

    Three

  • Option 4)

    Five

 

Answers (1)

As we have learned

Weak field Ligand -

These are the ligands which do not pair the electron in inner d-orbital.

- wherein

For example: N_{2}O, F^{-}, Cl^{-} etc    

 

 

  In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons = 5.


Option 1)

Two

Option 2)

Four

Option 3)

Three

Option 4)

Five

Posted by

Vakul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Parents paid FIITJEE coaching fees from life insurance payouts, loans; they demand refunds
anam-khan

JEE Main session 2 registration 2025 begins today at jeemain.nta.nic.in; fee, document required
anam-khan

NTA JEE Main 2025 session 1 ends with 94.4% attendance; UGC NET records 76.5% participation

Latest Question