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  • Need clarity, kindly explain! - Electrostatics - JEE Main-9

The direction \left ( \theta \right ) of \overset {\rightarrow } E at point P due to uniformly charged finite rod will be

  • Option 1)

    30 ^{o} \; from \; X

  • Option 2)

    45^{o} \; from \; X

  • Option 3)

    60 ^{o} \; from \; X

  • Option 4)

    None

 

Answers (1)

best_answer

As we learned

If point P lies at Perpendicular bisector of wire -

\alpha = \beta

E_{x}=\frac{2k\lambda }{r}\sin \alpha

E_{y}=0

-

 

 

 

Using symmetry property


Option 1)

30 ^{o} \; from \; X

Option 2)

45^{o} \; from \; X

Option 3)

60 ^{o} \; from \; X

Option 4)

None

Posted by

Avinash

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