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  • Need clarity, kindly explain! In Young’s double slit experiment, 12 fringes are observed to be formed in a certain segment of the screen, when light of wavelength 800 nm is used. If the wavelength of light is changed to 400 nm, number of fringe

In Young’s double slit experiment, 12 fringes are observed to be formed in a certain segment of the screen, when light of wavelength 800 nm is used. If the wavelength of light is changed to 400 nm, number of fringes observed in the same segment of the screen is given by:

  • Option 1)

    12

  • Option 2)

    18

  • Option 3)

    24

  • Option 4)

    30

 

Answers (1)

 

Fringe Width -

\beta = \frac{\lambda D}{d}
 

- wherein

\beta = y_{n+1}-y_{n}

y_{n+1}= Distance of\left ( n+1 \right )^{th}

Maxima= \left ( n+1 \right )\frac{\lambda D}{d}

y_{n}=Distance of n^{th}

 maxima = \frac{n\lambda D}{d}

 

Fringe width \propto \lambda 

when we reduce wavelength to half, fringe width also become half . Hence double fringe can be accommodated in the same thickness.

Total number of fringes = 24


Option 1)

12

Incorrect

Option 2)

18

Incorrect

Option 3)

24

Correct

Option 4)

30

Incorrect

Posted by

Vakul

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