Q

# Need clarity, kindly explain! - Solutions - JEE Main-2

The osmotic pressure of a dilute solution of an ionic compound $XY$ in water is four times that of a solution of $0.01 \; M$ $BaCl_{2}$ in water. Assuming complete dissociation of the given ionic compounds in water, the concentration of $XY\left ( in \; mol\; L\; ^{-1} \right )$ in solution is :

• Option 1)

$4\times 10^{-2}$

• Option 2)

$6\times 10^{-2}$

• Option 3)

$4\times 10^{-4}$

• Option 4)

$16\times 10^{-4}$

Views

Given, $\pi _{xy}=4\pi _{BaCl_{2}}$

$i_{2}GRT=4i_{2}C_{2}RT$

$2\left [ xy \right ]=4\times 3\times \left [ 0.01 \right ]$

$\left [ xy \right ]=2\times 3\times 0.01=6\times 10^{-2}M$

Option 1)

$4\times 10^{-2}$

Option 2)

$6\times 10^{-2}$

Option 3)

$4\times 10^{-4}$

Option 4)

$16\times 10^{-4}$

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