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Need clarity, kindly explain! - Solutions - JEE Main-2

The osmotic pressure of a dilute solution of an ionic compound XY in water is four times that of a solution of 0.01 \; M BaCl_{2} in water. Assuming complete dissociation of the given ionic compounds in water, the concentration of XY\left ( in \; mol\; L\; ^{-1} \right ) in solution is :

  • Option 1)

     4\times 10^{-2}                

  • Option 2)

     6\times 10^{-2}

  • Option 3)

     4\times 10^{-4}

  • Option 4)

    16\times 10^{-4}

 
Answers (1)
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S solutionqc

Given, \pi _{xy}=4\pi _{BaCl_{2}}

     i_{2}GRT=4i_{2}C_{2}RT

2\left [ xy \right ]=4\times 3\times \left [ 0.01 \right ]

\left [ xy \right ]=2\times 3\times 0.01=6\times 10^{-2}M


Option 1)

 4\times 10^{-2}                

Option 2)

 6\times 10^{-2}

Option 3)

 4\times 10^{-4}

Option 4)

16\times 10^{-4}

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