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# Need clarity, kindly explain! The variation of acceleration due to gravity g with distance d from centre of the earth is best represented by(R=Earth’s radius) :

The variation of acceleration due to gravity g with distance d from centre of the earth is best represented by

• Option 1)

• Option 2)

• Option 3)

• Option 4)

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As we learnt in

Value of 'g' at ∞ -

$g'\alpha\: \frac{1}{r^{2}}$

if   $r=\infty \: \; \; \; \; \; \; g'=0$

$g'\rightarrow$ Value of acceleration due to gravity

$r\rightarrow$ height above earth's surface

- wherein

No effect of earth gravitational pull at infinite distance.

if $d      $g= \frac{Gm}{K^2}d$

$d=R,$           $g=\frac{Gm}{R^2}$

$d> R,$           $g=\frac{Gm}{d^2}$

i.e. $g \propto \frac{1}{d^2}$

Option 1)

Incorrect

Option 2)

Incorrect

Option 3)

Incorrect

Option 4)

Correct

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