Two beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the beams is p/2 at point A and p at point B. Then the difference between the resultant intensities at A and B is:

  • Option 1)

    2I

  • Option 2)

    4I

  • Option 3)

    5I

  • Option 4)

    7I

 

Answers (1)

 

Resultant Intensity of two wave -

I= I_{1}+I_{2}+2\sqrt{I_{1}I_{2}}\cos \theta

- wherein

I_{1}= Intencity of wave 1

I_{2}= Intencity of wave 2

\theta = Phase difference

 

 

 I_{A} = I+4I+2\sqrt{I.4I}.\cos \frac{\pi }{2} =5I

I_{B} = I+4I+2\sqrt{I.4I}.\cos \pi =I

I_{A}-I_{B} = 4I 


Option 1)

2I

Incorrect

Option 2)

4I

Correct

Option 3)

5I

Incorrect

Option 4)

7I

Incorrect

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