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What volume of H2 is required to produce NH3 if we have 22.4L of N2 available at STP and no Nis left ?

  • Option 1)

    89.6 L

  • Option 2)

    67.2 L

  • Option 3)

    44.8 L

  • Option 4)

    22.4 L

 

Answers (1)

As we learnt

 

Gay Lussac's law of Gaseous Volumes -

When gases combine or are poduced in a chemical reaction, they do so in a simple ratio by volume provided all gases are at the same temperature and pressure.

- wherein

H_{2}}_{(g)} + {O_{2}}_{(g)} \rightarrow {H_{2}O}_{(g)}

100 ml        50ml            100ml

 

 

N_{2} + 3H_{2} \rightarrow 2NH_{3}

22.4      x                0

By Gay Lussac's Law:

x = 3\times 22.4 = 67.2L

\therefore Solution is B

 


Option 1)

89.6 L

This is  incorrect.

Option 2)

67.2 L

This is correct.

Option 3)

44.8 L

This is  incorrect.

Option 4)

22.4 L

This is  incorrect.

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subam

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