# An amount of solid is placed in a flask already containing ammonia gas at a certain temperature and pressure. Ammonium hydrogen sulphide decomposes to yield  gases in the flask. When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.85 atm. The equilibrium constant for decomposition at this temperature is Option 1) Option 2) Option 3) Option 4)

As we learnt in

Relation between pressure and concentration -

- wherein

P is pressure in Pa. C is concentration in mol / litre. T is temperature in kelvin

and

Law of Chemical equilibrium -

At a given temperature, the product of concentration of the reaction products raised to the respective stoichiometric coefficient in the balanced chemical equation divided by the product of concentration of the reactants raised to their individual stoichiometric coefficients has a constant value.

- wherein

are equilibrium concentration

Initial pressure             0                                0.5                    0

At equi.                         0                            0.5 + x                  x

Total pressure = 0.5 + 2x = 0.84

x = 0.17 atm

Option 1)

This option is incorrect

Option 2)

This option is incorrect

Option 3)

This option is incorrect

Option 4)

This option is correct

## Most Viewed Questions

### Preparation Products

##### Knockout JEE Main April 2021 (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 14000/- ₹ 4999/-
##### Knockout JEE Main May 2021

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 22999/- ₹ 9999/-
##### Test Series JEE Main May 2021

Unlimited Chapter Wise Tests, Unlimited Subject Wise Tests, Unlimited Full Mock Tests, Get Personalized Performance Analysis Report,.

₹ 6999/- ₹ 2999/-
##### Knockout JEE Main May 2022

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 34999/- ₹ 14999/-