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  • Need explanation for: PQR is a triangular park with PQ=PR=200 m. A T.V. tower stands at the mid-point of QR. If the angles of elevation of the top of the tower at P, Qand R are respectively 45º, 30ºand 30º, then the height of the tower

PQR is a triangular park with PQ=PR=200 m. A T.V. tower stands at the mid-point of QR. If the angles of  elevation of the top of the tower at P, Q
and R are respectively 45º, 30º and 30º, then the height of the tower (in m) is :

  • Option 1)

    50\sqrt{2}

  • Option 2)

    100

  • Option 3)

    50

  • Option 4)

    100{\sqrt3}

 

Answers (2)

best_answer

\tan 30\degree= \frac{MN}{QM}=\frac{h}{QM}=\frac{1}{\sqrt3}

QM = \sqrt3h = MR

In \Delta PMQ

(PQ)^{2}= (MP)^{2}+(MQ)^{2}

(200)^{2}= (h)^{2}+(3h)^{2}

h= 100m

 

Angle of Depression -

If an object is below the horizontal line from the eye, we have to lower our head to view the object.

- wherein

angle of depression

 

 


Option 1)

50\sqrt{2}

Option 2)

100

Option 3)

50

Option 4)

100{\sqrt3}

Posted by

Himanshu

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