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Number of Divisor of 1440 is 

Option: 1

 9 


Option: 2

12 


Option: 3

24 


Option: 4

36 


Answers (1)

best_answer

As we have learned,

The number of divisors of a natural number 

n=(a_{1})^{k_{1}}(a_{2})^{k_{2}}..............(a_{m})^{k_{m}} is 

(k_{1}+1)(k_{2}+1)..........(k_{m}+1)

Where a1, a2 ....... are distinct prime numbers

 

Now,

 1440 = 2 ^ 5 \times 3 ^2 \times 5 ^1

No. of divisior = (5+1)(2+1)(1+1)= 6 \times 3 \times 2= 36 

 

 

 

 

 

Posted by

himanshu.meshram

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